Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 1 | // Copyright 2009 The Go Authors. All rights reserved. |
| 2 | // Use of this source code is governed by a BSD-style |
| 3 | // license that can be found in the LICENSE file. |
| 4 | |
Nigel Tao | 4c1e1b8 | 2011-05-09 17:25:32 -0700 | [diff] [blame] | 5 | package jpeg |
| 6 | |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 7 | // This is a Go translation of idct.c from |
| 8 | // |
| 9 | // http://standards.iso.org/ittf/PubliclyAvailableStandards/ISO_IEC_13818-4_2004_Conformance_Testing/Video/verifier/mpeg2decode_960109.tar.gz |
| 10 | // |
| 11 | // which carries the following notice: |
| 12 | |
| 13 | /* Copyright (C) 1996, MPEG Software Simulation Group. All Rights Reserved. */ |
| 14 | |
| 15 | /* |
| 16 | * Disclaimer of Warranty |
| 17 | * |
| 18 | * These software programs are available to the user without any license fee or |
| 19 | * royalty on an "as is" basis. The MPEG Software Simulation Group disclaims |
| 20 | * any and all warranties, whether express, implied, or statuary, including any |
| 21 | * implied warranties or merchantability or of fitness for a particular |
| 22 | * purpose. In no event shall the copyright-holder be liable for any |
| 23 | * incidental, punitive, or consequential damages of any kind whatsoever |
| 24 | * arising from the use of these programs. |
| 25 | * |
| 26 | * This disclaimer of warranty extends to the user of these programs and user's |
| 27 | * customers, employees, agents, transferees, successors, and assigns. |
| 28 | * |
| 29 | * The MPEG Software Simulation Group does not represent or warrant that the |
| 30 | * programs furnished hereunder are free of infringement of any third-party |
| 31 | * patents. |
| 32 | * |
| 33 | * Commercial implementations of MPEG-1 and MPEG-2 video, including shareware, |
| 34 | * are subject to royalty fees to patent holders. Many of these patents are |
| 35 | * general enough such that they are unavoidable regardless of implementation |
| 36 | * design. |
| 37 | * |
| 38 | */ |
| 39 | |
Nigel Tao | 12e343f | 2012-10-07 10:21:17 +1100 | [diff] [blame] | 40 | const blockSize = 64 // A DCT block is 8x8. |
| 41 | |
Nigel Tao | daf43ba | 2012-10-30 11:10:08 +1100 | [diff] [blame] | 42 | type block [blockSize]int32 |
Nigel Tao | 12e343f | 2012-10-07 10:21:17 +1100 | [diff] [blame] | 43 | |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 44 | const ( |
| 45 | w1 = 2841 // 2048*sqrt(2)*cos(1*pi/16) |
| 46 | w2 = 2676 // 2048*sqrt(2)*cos(2*pi/16) |
| 47 | w3 = 2408 // 2048*sqrt(2)*cos(3*pi/16) |
| 48 | w5 = 1609 // 2048*sqrt(2)*cos(5*pi/16) |
| 49 | w6 = 1108 // 2048*sqrt(2)*cos(6*pi/16) |
| 50 | w7 = 565 // 2048*sqrt(2)*cos(7*pi/16) |
| 51 | |
| 52 | w1pw7 = w1 + w7 |
| 53 | w1mw7 = w1 - w7 |
| 54 | w2pw6 = w2 + w6 |
| 55 | w2mw6 = w2 - w6 |
| 56 | w3pw5 = w3 + w5 |
| 57 | w3mw5 = w3 - w5 |
| 58 | |
| 59 | r2 = 181 // 256/sqrt(2) |
| 60 | ) |
| 61 | |
Nigel Tao | 0b9fe6d | 2012-10-07 11:32:02 +1100 | [diff] [blame] | 62 | // idct performs a 2-D Inverse Discrete Cosine Transformation. |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 63 | // |
Nigel Tao | 4c1e1b8 | 2011-05-09 17:25:32 -0700 | [diff] [blame] | 64 | // The input coefficients should already have been multiplied by the |
| 65 | // appropriate quantization table. We use fixed-point computation, with the |
| 66 | // number of bits for the fractional component varying over the intermediate |
| 67 | // stages. |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 68 | // |
Nigel Tao | 4c1e1b8 | 2011-05-09 17:25:32 -0700 | [diff] [blame] | 69 | // For more on the actual algorithm, see Z. Wang, "Fast algorithms for the |
| 70 | // discrete W transform and for the discrete Fourier transform", IEEE Trans. on |
| 71 | // ASSP, Vol. ASSP- 32, pp. 803-816, Aug. 1984. |
Nigel Tao | 0b9fe6d | 2012-10-07 11:32:02 +1100 | [diff] [blame] | 72 | func idct(src *block) { |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 73 | // Horizontal 1-D IDCT. |
| 74 | for y := 0; y < 8; y++ { |
Nigel Tao | 12e343f | 2012-10-07 10:21:17 +1100 | [diff] [blame] | 75 | y8 := y * 8 |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 76 | // If all the AC components are zero, then the IDCT is trivial. |
Nigel Tao | 12e343f | 2012-10-07 10:21:17 +1100 | [diff] [blame] | 77 | if src[y8+1] == 0 && src[y8+2] == 0 && src[y8+3] == 0 && |
| 78 | src[y8+4] == 0 && src[y8+5] == 0 && src[y8+6] == 0 && src[y8+7] == 0 { |
| 79 | dc := src[y8+0] << 3 |
| 80 | src[y8+0] = dc |
| 81 | src[y8+1] = dc |
| 82 | src[y8+2] = dc |
| 83 | src[y8+3] = dc |
| 84 | src[y8+4] = dc |
| 85 | src[y8+5] = dc |
| 86 | src[y8+6] = dc |
| 87 | src[y8+7] = dc |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 88 | continue |
| 89 | } |
| 90 | |
| 91 | // Prescale. |
Nigel Tao | 12e343f | 2012-10-07 10:21:17 +1100 | [diff] [blame] | 92 | x0 := (src[y8+0] << 11) + 128 |
| 93 | x1 := src[y8+4] << 11 |
| 94 | x2 := src[y8+6] |
| 95 | x3 := src[y8+2] |
| 96 | x4 := src[y8+1] |
| 97 | x5 := src[y8+7] |
| 98 | x6 := src[y8+5] |
| 99 | x7 := src[y8+3] |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 100 | |
| 101 | // Stage 1. |
| 102 | x8 := w7 * (x4 + x5) |
| 103 | x4 = x8 + w1mw7*x4 |
| 104 | x5 = x8 - w1pw7*x5 |
| 105 | x8 = w3 * (x6 + x7) |
| 106 | x6 = x8 - w3mw5*x6 |
| 107 | x7 = x8 - w3pw5*x7 |
| 108 | |
| 109 | // Stage 2. |
| 110 | x8 = x0 + x1 |
| 111 | x0 -= x1 |
| 112 | x1 = w6 * (x3 + x2) |
| 113 | x2 = x1 - w2pw6*x2 |
| 114 | x3 = x1 + w2mw6*x3 |
| 115 | x1 = x4 + x6 |
| 116 | x4 -= x6 |
| 117 | x6 = x5 + x7 |
| 118 | x5 -= x7 |
| 119 | |
| 120 | // Stage 3. |
| 121 | x7 = x8 + x3 |
| 122 | x8 -= x3 |
| 123 | x3 = x0 + x2 |
| 124 | x0 -= x2 |
| 125 | x2 = (r2*(x4+x5) + 128) >> 8 |
| 126 | x4 = (r2*(x4-x5) + 128) >> 8 |
| 127 | |
| 128 | // Stage 4. |
Nigel Tao | 12e343f | 2012-10-07 10:21:17 +1100 | [diff] [blame] | 129 | src[y8+0] = (x7 + x1) >> 8 |
| 130 | src[y8+1] = (x3 + x2) >> 8 |
| 131 | src[y8+2] = (x0 + x4) >> 8 |
| 132 | src[y8+3] = (x8 + x6) >> 8 |
| 133 | src[y8+4] = (x8 - x6) >> 8 |
| 134 | src[y8+5] = (x0 - x4) >> 8 |
| 135 | src[y8+6] = (x3 - x2) >> 8 |
| 136 | src[y8+7] = (x7 - x1) >> 8 |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 137 | } |
| 138 | |
| 139 | // Vertical 1-D IDCT. |
| 140 | for x := 0; x < 8; x++ { |
| 141 | // Similar to the horizontal 1-D IDCT case, if all the AC components are zero, then the IDCT is trivial. |
| 142 | // However, after performing the horizontal 1-D IDCT, there are typically non-zero AC components, so |
| 143 | // we do not bother to check for the all-zero case. |
| 144 | |
| 145 | // Prescale. |
Nigel Tao | 4c1e1b8 | 2011-05-09 17:25:32 -0700 | [diff] [blame] | 146 | y0 := (src[8*0+x] << 8) + 8192 |
| 147 | y1 := src[8*4+x] << 8 |
| 148 | y2 := src[8*6+x] |
| 149 | y3 := src[8*2+x] |
| 150 | y4 := src[8*1+x] |
| 151 | y5 := src[8*7+x] |
| 152 | y6 := src[8*5+x] |
| 153 | y7 := src[8*3+x] |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 154 | |
| 155 | // Stage 1. |
| 156 | y8 := w7*(y4+y5) + 4 |
| 157 | y4 = (y8 + w1mw7*y4) >> 3 |
| 158 | y5 = (y8 - w1pw7*y5) >> 3 |
| 159 | y8 = w3*(y6+y7) + 4 |
| 160 | y6 = (y8 - w3mw5*y6) >> 3 |
| 161 | y7 = (y8 - w3pw5*y7) >> 3 |
| 162 | |
| 163 | // Stage 2. |
| 164 | y8 = y0 + y1 |
| 165 | y0 -= y1 |
| 166 | y1 = w6*(y3+y2) + 4 |
| 167 | y2 = (y1 - w2pw6*y2) >> 3 |
| 168 | y3 = (y1 + w2mw6*y3) >> 3 |
| 169 | y1 = y4 + y6 |
| 170 | y4 -= y6 |
| 171 | y6 = y5 + y7 |
| 172 | y5 -= y7 |
| 173 | |
| 174 | // Stage 3. |
| 175 | y7 = y8 + y3 |
| 176 | y8 -= y3 |
| 177 | y3 = y0 + y2 |
| 178 | y0 -= y2 |
| 179 | y2 = (r2*(y4+y5) + 128) >> 8 |
| 180 | y4 = (r2*(y4-y5) + 128) >> 8 |
| 181 | |
| 182 | // Stage 4. |
Nigel Tao | 4c1e1b8 | 2011-05-09 17:25:32 -0700 | [diff] [blame] | 183 | src[8*0+x] = (y7 + y1) >> 14 |
| 184 | src[8*1+x] = (y3 + y2) >> 14 |
| 185 | src[8*2+x] = (y0 + y4) >> 14 |
| 186 | src[8*3+x] = (y8 + y6) >> 14 |
| 187 | src[8*4+x] = (y8 - y6) >> 14 |
| 188 | src[8*5+x] = (y0 - y4) >> 14 |
| 189 | src[8*6+x] = (y3 - y2) >> 14 |
| 190 | src[8*7+x] = (y7 - y1) >> 14 |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 191 | } |
Nigel Tao | 8bf5872 | 2009-12-17 10:32:17 +1100 | [diff] [blame] | 192 | } |