compiler: don't warn for print()
We used to warn for calls to print(), because it doesn't do anything.
However, a Go 1.18 test uses that call, and it is valid Go. Change
the compiler to just accept it and compile it; this will produce calls
to printlock and printunlock, and nothing else.
Change-Id: I11710ae38478d1860cf8e2708bec8b0f7e1b8373
Reviewed-on: https://go-review.googlesource.com/c/gofrontend/+/384355
Trust: Ian Lance Taylor <iant@golang.org>
Reviewed-by: Cherry Mui <cherryyz@google.com>
Reviewed-by: Than McIntosh <thanm@google.com>
diff --git a/go/expressions.cc b/go/expressions.cc
index 3f59765..1b3b3bf 100644
--- a/go/expressions.cc
+++ b/go/expressions.cc
@@ -10332,16 +10332,7 @@
case BUILTIN_PRINTLN:
{
const Expression_list* args = this->args();
- if (args == NULL)
- {
- if (this->code_ == BUILTIN_PRINT)
- go_warning_at(this->location(), 0,
- "no arguments for built-in function %<%s%>",
- (this->code_ == BUILTIN_PRINT
- ? "print"
- : "println"));
- }
- else
+ if (args != NULL)
{
for (Expression_list::const_iterator p = args->begin();
p != args->end();
