| /* | |
| * The authors of this software are Rob Pike and Ken Thompson. | |
| * Copyright (c) 2002 by Lucent Technologies. | |
| * Portions Copyright 2009 The Go Authors. All rights reserved. | |
| * Permission to use, copy, modify, and distribute this software for any | |
| * purpose without fee is hereby granted, provided that this entire notice | |
| * is included in all copies of any software which is or includes a copy | |
| * or modification of this software and in all copies of the supporting | |
| * documentation for such software. | |
| * THIS SOFTWARE IS BEING PROVIDED "AS IS", WITHOUT ANY EXPRESS OR IMPLIED | |
| * WARRANTY. IN PARTICULAR, NEITHER THE AUTHORS NOR LUCENT TECHNOLOGIES MAKE ANY | |
| * REPRESENTATION OR WARRANTY OF ANY KIND CONCERNING THE MERCHANTABILITY | |
| * OF THIS SOFTWARE OR ITS FITNESS FOR ANY PARTICULAR PURPOSE. | |
| */ | |
| /* | |
| * This code is copied, with slight editing due to type differences, | |
| * from a subset of ../lib9/utf/rune.c [which no longer exists] | |
| */ | |
| package runtime | |
| const ( | |
| bit1 = 7 | |
| bitx = 6 | |
| bit2 = 5 | |
| bit3 = 4 | |
| bit4 = 3 | |
| bit5 = 2 | |
| t1 = ((1 << (bit1 + 1)) - 1) ^ 0xFF /* 0000 0000 */ | |
| tx = ((1 << (bitx + 1)) - 1) ^ 0xFF /* 1000 0000 */ | |
| t2 = ((1 << (bit2 + 1)) - 1) ^ 0xFF /* 1100 0000 */ | |
| t3 = ((1 << (bit3 + 1)) - 1) ^ 0xFF /* 1110 0000 */ | |
| t4 = ((1 << (bit4 + 1)) - 1) ^ 0xFF /* 1111 0000 */ | |
| t5 = ((1 << (bit5 + 1)) - 1) ^ 0xFF /* 1111 1000 */ | |
| rune1 = (1 << (bit1 + 0*bitx)) - 1 /* 0000 0000 0111 1111 */ | |
| rune2 = (1 << (bit2 + 1*bitx)) - 1 /* 0000 0111 1111 1111 */ | |
| rune3 = (1 << (bit3 + 2*bitx)) - 1 /* 1111 1111 1111 1111 */ | |
| rune4 = (1 << (bit4 + 3*bitx)) - 1 /* 0001 1111 1111 1111 1111 1111 */ | |
| maskx = (1 << bitx) - 1 /* 0011 1111 */ | |
| testx = maskx ^ 0xFF /* 1100 0000 */ | |
| runeerror = 0xFFFD | |
| runeself = 0x80 | |
| surrogateMin = 0xD800 | |
| surrogateMax = 0xDFFF | |
| bad = runeerror | |
| runemax = 0x10FFFF /* maximum rune value */ | |
| ) | |
| /* | |
| * Modified by Wei-Hwa Huang, Google Inc., on 2004-09-24 | |
| * This is a slower but "safe" version of the old chartorune | |
| * that works on strings that are not necessarily null-terminated. | |
| * | |
| * If you know for sure that your string is null-terminated, | |
| * chartorune will be a bit faster. | |
| * | |
| * It is guaranteed not to attempt to access "length" | |
| * past the incoming pointer. This is to avoid | |
| * possible access violations. If the string appears to be | |
| * well-formed but incomplete (i.e., to get the whole Rune | |
| * we'd need to read past str+length) then we'll set the Rune | |
| * to Bad and return 0. | |
| * | |
| * Note that if we have decoding problems for other | |
| * reasons, we return 1 instead of 0. | |
| */ | |
| func charntorune(s string) (rune, int) { | |
| /* When we're not allowed to read anything */ | |
| if len(s) <= 0 { | |
| return bad, 1 | |
| } | |
| /* | |
| * one character sequence (7-bit value) | |
| * 00000-0007F => T1 | |
| */ | |
| c := s[0] | |
| if c < tx { | |
| return rune(c), 1 | |
| } | |
| // If we can't read more than one character we must stop | |
| if len(s) <= 1 { | |
| return bad, 1 | |
| } | |
| /* | |
| * two character sequence (11-bit value) | |
| * 0080-07FF => t2 tx | |
| */ | |
| c1 := s[1] ^ tx | |
| if (c1 & testx) != 0 { | |
| return bad, 1 | |
| } | |
| if c < t3 { | |
| if c < t2 { | |
| return bad, 1 | |
| } | |
| l := ((rune(c) << bitx) | rune(c1)) & rune2 | |
| if l <= rune1 { | |
| return bad, 1 | |
| } | |
| return l, 2 | |
| } | |
| // If we can't read more than two characters we must stop | |
| if len(s) <= 2 { | |
| return bad, 1 | |
| } | |
| /* | |
| * three character sequence (16-bit value) | |
| * 0800-FFFF => t3 tx tx | |
| */ | |
| c2 := s[2] ^ tx | |
| if (c2 & testx) != 0 { | |
| return bad, 1 | |
| } | |
| if c < t4 { | |
| l := ((((rune(c) << bitx) | rune(c1)) << bitx) | rune(c2)) & rune3 | |
| if l <= rune2 { | |
| return bad, 1 | |
| } | |
| if surrogateMin <= l && l <= surrogateMax { | |
| return bad, 1 | |
| } | |
| return l, 3 | |
| } | |
| if len(s) <= 3 { | |
| return bad, 1 | |
| } | |
| /* | |
| * four character sequence (21-bit value) | |
| * 10000-1FFFFF => t4 tx tx tx | |
| */ | |
| c3 := s[3] ^ tx | |
| if (c3 & testx) != 0 { | |
| return bad, 1 | |
| } | |
| if c < t5 { | |
| l := ((((((rune(c) << bitx) | rune(c1)) << bitx) | rune(c2)) << bitx) | rune(c3)) & rune4 | |
| if l <= rune3 || l > runemax { | |
| return bad, 1 | |
| } | |
| return l, 4 | |
| } | |
| // Support for 5-byte or longer UTF-8 would go here, but | |
| // since we don't have that, we'll just return bad. | |
| return bad, 1 | |
| } | |
| // runetochar converts r to bytes and writes the result to str. | |
| // returns the number of bytes generated. | |
| func runetochar(str []byte, r rune) int { | |
| /* runes are signed, so convert to unsigned for range check. */ | |
| c := uint32(r) | |
| /* | |
| * one character sequence | |
| * 00000-0007F => 00-7F | |
| */ | |
| if c <= rune1 { | |
| str[0] = byte(c) | |
| return 1 | |
| } | |
| /* | |
| * two character sequence | |
| * 0080-07FF => t2 tx | |
| */ | |
| if c <= rune2 { | |
| str[0] = byte(t2 | (c >> (1 * bitx))) | |
| str[1] = byte(tx | (c & maskx)) | |
| return 2 | |
| } | |
| /* | |
| * If the rune is out of range or a surrogate half, convert it to the error rune. | |
| * Do this test here because the error rune encodes to three bytes. | |
| * Doing it earlier would duplicate work, since an out of range | |
| * rune wouldn't have fit in one or two bytes. | |
| */ | |
| if c > runemax { | |
| c = runeerror | |
| } | |
| if surrogateMin <= c && c <= surrogateMax { | |
| c = runeerror | |
| } | |
| /* | |
| * three character sequence | |
| * 0800-FFFF => t3 tx tx | |
| */ | |
| if c <= rune3 { | |
| str[0] = byte(t3 | (c >> (2 * bitx))) | |
| str[1] = byte(tx | ((c >> (1 * bitx)) & maskx)) | |
| str[2] = byte(tx | (c & maskx)) | |
| return 3 | |
| } | |
| /* | |
| * four character sequence (21-bit value) | |
| * 10000-1FFFFF => t4 tx tx tx | |
| */ | |
| str[0] = byte(t4 | (c >> (3 * bitx))) | |
| str[1] = byte(tx | ((c >> (2 * bitx)) & maskx)) | |
| str[2] = byte(tx | ((c >> (1 * bitx)) & maskx)) | |
| str[3] = byte(tx | (c & maskx)) | |
| return 4 | |
| } |