go/parser: remove unused method checkBinaryExpr
Change-Id: Ica981657e50e30cbfa1757e8457819a479f11c7d
Reviewed-on: https://go-review.googlesource.com/c/go/+/412775
Reviewed-by: Ian Lance Taylor <iant@google.com>
TryBot-Result: Gopher Robot <gobot@golang.org>
Auto-Submit: Robert Griesemer <gri@google.com>
Run-TryBot: Robert Griesemer <gri@google.com>
Reviewed-by: Robert Griesemer <gri@google.com>
diff --git a/src/go/parser/parser.go b/src/go/parser/parser.go
index 18041ff..ca2f24c 100644
--- a/src/go/parser/parser.go
+++ b/src/go/parser/parser.go
@@ -1821,23 +1821,6 @@
}
}
-// checkBinaryExpr checks binary expressions that were not already checked by
-// parseBinaryExpr, because the latter was called with check=false.
-func (p *parser) checkBinaryExpr(x ast.Expr) {
- bx, ok := x.(*ast.BinaryExpr)
- if !ok {
- return
- }
-
- bx.X = p.checkExpr(bx.X)
- bx.Y = p.checkExpr(bx.Y)
-
- // parseBinaryExpr checks x and y for each binary expr in a tree, so we
- // traverse the tree of binary exprs starting from x.
- p.checkBinaryExpr(bx.X)
- p.checkBinaryExpr(bx.Y)
-}
-
// The result may be a type or even a raw type ([...]int). Callers must
// check the result (using checkExpr or checkExprOrType), depending on
// context.
