|  | // run | 
|  |  | 
|  | // Copyright 2009 The Go Authors. All rights reserved. | 
|  | // Use of this source code is governed by a BSD-style | 
|  | // license that can be found in the LICENSE file. | 
|  |  | 
|  | // Test stack splitting code. | 
|  | // Try to tickle stack splitting bugs by doing | 
|  | // go, defer, and closure calls at different stack depths. | 
|  |  | 
|  | package main | 
|  |  | 
|  | type T [20]int | 
|  |  | 
|  | func g(c chan int, t T) { | 
|  | s := 0 | 
|  | for i := 0; i < len(t); i++ { | 
|  | s += t[i] | 
|  | } | 
|  | c <- s | 
|  | } | 
|  |  | 
|  | func d(t T) { | 
|  | s := 0 | 
|  | for i := 0; i < len(t); i++ { | 
|  | s += t[i] | 
|  | } | 
|  | if s != len(t) { | 
|  | println("bad defer", s) | 
|  | panic("fail") | 
|  | } | 
|  | } | 
|  |  | 
|  | func f0() { | 
|  | // likely to make a new stack for f0, | 
|  | // because the call to f1 puts 3000 bytes | 
|  | // in our frame. | 
|  | f1() | 
|  | } | 
|  |  | 
|  | func f1() [3000]byte { | 
|  | // likely to make a new stack for f1, | 
|  | // because 3000 bytes were used by f0 | 
|  | // and we need 3000 more for the call | 
|  | // to f2.  if the call to morestack in f1 | 
|  | // does not pass the frame size, the new | 
|  | // stack (default size 5k) will not be big | 
|  | // enough for the frame, and the morestack | 
|  | // check in f2 will die, if we get that far | 
|  | // without faulting. | 
|  | f2() | 
|  | return [3000]byte{} | 
|  | } | 
|  |  | 
|  | func f2() [3000]byte { | 
|  | // just take up space | 
|  | return [3000]byte{} | 
|  | } | 
|  |  | 
|  | var c = make(chan int) | 
|  | var t T | 
|  | var b = []byte{1, 2, 3, 4, 5, 6, 7, 8, 9, 10} | 
|  |  | 
|  | func recur(n int) { | 
|  | ss := string(b) | 
|  | if len(ss) != len(b) { | 
|  | panic("bad []byte -> string") | 
|  | } | 
|  | go g(c, t) | 
|  | f0() | 
|  | s := <-c | 
|  | if s != len(t) { | 
|  | println("bad go", s) | 
|  | panic("fail") | 
|  | } | 
|  | f := func(t T) int { | 
|  | s := 0 | 
|  | for i := 0; i < len(t); i++ { | 
|  | s += t[i] | 
|  | } | 
|  | s += n | 
|  | return s | 
|  | } | 
|  | s = f(t) | 
|  | if s != len(t)+n { | 
|  | println("bad func", s, "at level", n) | 
|  | panic("fail") | 
|  | } | 
|  | if n > 0 { | 
|  | recur(n - 1) | 
|  | } | 
|  | defer d(t) | 
|  | } | 
|  |  | 
|  | func main() { | 
|  | for i := 0; i < len(t); i++ { | 
|  | t[i] = 1 | 
|  | } | 
|  | recur(8000) | 
|  | } |