| --- |
| title: InterfaceSlice |
| --- |
| |
| ## Introduction |
| |
| Given that you can assign a variable of any type to an ` interface{} `, often people will try code like the following. |
| ```go |
| var dataSlice []int = foo() |
| var interfaceSlice []interface{} = dataSlice |
| ``` |
| This gets the error |
| ``` |
| cannot use dataSlice (type []int) as type []interface { } in assignment |
| ``` |
| |
| The question then, "Why can't I assign any slice to an ` []interface{} `, when I can assign any type to an ` interface{} `?" |
| |
| ### Why? |
| |
| There are two main reasons for this. |
| |
| The first is that a variable with type ` []interface{} ` is not an interface! It is a slice whose element type happens to be ` interface{} `. But even given this, one might say that the meaning is clear. |
| |
| Well, is it? A variable with type ` []interface{} ` has a specific memory layout, known at compile time. |
| |
| Each ` interface{} ` takes up two words (one word for the type of what is contained, the other word for either the contained data or a pointer to it). As a consequence, a slice with length N and with type ` []interface{} ` is backed by a chunk of data that is N\*2 words long. |
| |
| This is different than the chunk of data backing a slice with type ` []MyType ` and the same length. Its chunk of data will be N\*sizeof(MyType) words long. |
| |
| The result is that you cannot quickly assign something of type ` []MyType ` to something of type ` []interface{} `; the data behind them just look different. |
| |
| ### What can I do instead? |
| |
| It depends on what you wanted to do in the first place. |
| |
| If you want a container for an arbitrary array type, and you plan on changing back to the original type before doing any indexing operations, you can just use an ` interface{} `. The code will be generic (if not compile-time type-safe) and fast. |
| |
| If you really want a ` []interface{} ` because you'll be doing indexing before converting back, or you are using a particular interface type and you want to use its methods, you will have to make a copy of the slice. |
| ```go |
| var dataSlice []int = foo() |
| var interfaceSlice []interface{} = make([]interface{}, len(dataSlice)) |
| for i, d := range dataSlice { |
| interfaceSlice[i] = d |
| } |
| ``` |