content/go-maps-in-action: remove line about random iteration order

This article is cited as a source of confusion on whether map iteration is "random",
something that is objectively correct because woefully underdefined, but that some
have assumed to mean "uniformly random" - which is not:

- https://twitter.com/wallyqs/status/1135719212024909824
- https://twitter.com/ultimateboy/status/1135325432624975872

Based on golang.org/cl/180457 by Carlo Alberto Ferraris

Change-Id: I2b75bc1ce592502fc1ddeb941a5a258dcb1925a1
Reviewed-on: https://go-review.googlesource.com/c/blog/+/197238
Reviewed-by: Bryan C. Mills <bcmills@google.com>
diff --git a/content/go-maps-in-action.article b/content/go-maps-in-action.article
index 7cca838..cc6d62c 100644
--- a/content/go-maps-in-action.article
+++ b/content/go-maps-in-action.article
@@ -156,7 +156,7 @@
 
 To read from the counter, take the read lock:
 
- 
+
 	counter.RLock()
 	n := counter.m["some_key"]
 	counter.RUnlock()
@@ -171,8 +171,6 @@
 * Iteration order
 
 When iterating over a map with a range loop, the iteration order is not specified and is not guaranteed to be the same from one iteration to the next.
-Since the release of Go 1.0, the runtime has randomized map iteration order.
-Programmers had begun to rely on the stable iteration order of early versions of Go, which varied between implementations, leading to portability bugs.
 If you require a stable iteration order you must maintain a separate data structure that specifies that order.
 This example uses a separate sorted slice of keys to print a `map[int]string` in key order: